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2.1Substitution: put the number in the brackets
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A taxi charges 4 + 2d dollars for a ride of d kilometres. Ride 7 km and you pay 4 + 2(7) = $18. A formula is a machine: a number goes in, a number comes out. Putting the number in is called substitution, and it is the first skill of this whole chapter.

Guess firstNo marks. Just a guess.
Guess first: if x = βˆ’5, what is xΒ²?

Swap the letter for its number, in brackets, then BEDMAS

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A variable is a letter that stands for a number. In 3x + 2 the letter x can be any number. A number written right beside a letter means multiply: 3x means 3 Γ— x, and 2(y + z) means 2 Γ— (y + z). To substitute is to replace each letter with its number. To evaluate is to then work out the answer.

The golden rule: every time you put a number in for a letter, put it in brackets. If x = βˆ’5, then 3x becomes 3(βˆ’5) = βˆ’15 and xΒ² becomes (βˆ’5)Β² = 25. The brackets keep the negative sign attached to its number, so nothing gets lost.

Quick checkIf x = βˆ’5, what is xΒ²?

After the numbers are in, follow BEDMAS: Brackets, Exponents, Division and Multiplication left to right, Addition and Subtraction left to right. Evaluate 3zΒ² βˆ’ x when z = 2 and x = βˆ’5: write 3(2)Β² βˆ’ (βˆ’5). Exponent first: (2)Β² = 4. Multiply: 3 Γ— 4 = 12. Subtracting a negative is adding: 12 + 5 = 17.

A fraction bar or a division sign between brackets works like brackets too: finish the top and the bottom before you divide. (m + n) Γ· (m βˆ’ n) with m = 4 and n = 6 is (4 + 6) Γ· (4 βˆ’ 6) = 10 Γ· (βˆ’2) = βˆ’5.

A table of values is the same expression with several inputs. For 2x βˆ’ 3: x = 1 gives 2(1) βˆ’ 3 = βˆ’1, x = 0 gives βˆ’3, x = βˆ’1 gives βˆ’5, x = βˆ’2 gives βˆ’7. Notice each output drops by 2 when x drops by 1: the coefficient 2 is the step.

Quick checkEvaluate βˆ’nΒ² + 5 when n = βˆ’2.

With brackets in the expression you have two roads, and both arrive at the same answer. 4(3x βˆ’ 2y) with x = 3 and y = βˆ’4: distribute first to get 12x βˆ’ 8y = 12(3) βˆ’ 8(βˆ’4) = 36 + 32 = 68, or substitute first to get 4(9 + 8) = 4(17) = 68.

Quick checkEvaluate βˆ’2(x + 2y) when x = 3 and y = βˆ’4.
The formula, in words
value = expression with (number) in place of each letter
x, y, z
the letters, each standing for one number
( )
the brackets you put around every number you substitute
Say it in words

Swap each letter for its number wearing brackets, then work it out in BEDMAS order.

Key ideaReplace every letter with its number IN BRACKETS, then follow BEDMAS. (βˆ’5)Β² = 25 but βˆ’5Β² = βˆ’25. Subtracting a negative is adding.
Watch a teacherMath Antics Β· 11 min

Algebra Basics: What Is Algebra?

Watch for
  • How he explains a letter as a number that has not been decided yet.
  • Pause each time he swaps a letter for a number and say the answer before he does.
  • Why does a number beside a letter mean multiply?
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3Γ—(2)^2βˆ’(βˆ’5)
Brackets first
  1. 3 Γ— ( 2 ) ^ 2 βˆ’ ( βˆ’5 )
Evaluate 4x βˆ’ 3y + 2(y + z) when x = βˆ’5, y = 10 and z = 2.
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